hi all,

don't know if anyone can help me, but I've hit a brick wall with regex, I'm trying to set up a filter in a widget to split long text into multiple lines so trying to get a regex that'll count up letters/spaces to a certain point. has anyone managed to do this? and would you be willing to share the secret?

Cheers

Tian

Hi,

I may be able to help but I will need an example of the text you are trying to cut up.

D.

Cheers,
I've sent you a mail with some details

Tian

Hi,

Got your email.

Working on it now. I have a basic version working but I want to improve its reliability.

D.

Hi,
Sorry for the delay, I have been swamped.

Here is what I came up with.

It is difficult to get this exact without lots of test data but this should work.
Using these filters:
Filter 1: (?<=SSE0\d{3}).{0,32}
Filter 2: (?<=SSE0\d{3}.{32}).{0,32}
Filter 3: (?<=SSE0\d{3}.{64}).{0,32}
Filter 4: (?<=SSE0\d{3}.{96}).{0,32}
Filter 5: (?<=SSE0\d{3}.{128}).{0,32}

I would make each line longer so that you don’t need as many lines of text (filters).

I am assuming (dangerous I know) that the test data has one thing that will always appear in the real data.
1. That after SSE0 there is ALWAYS 3 digits before the shows text.

I cannot guarantee it will always work correctly at the end of the text as each show will have different lengths of data. Only testing will show.

Here is the test data I used:
SSE0157Admiral Chegwidden and Clayton Webb make an unlikely team when they join forces to save a CIA agent from Italian terrorists. Starring: Catherine Bell.b3

The other issue is that the "b3" will show in the text as we do not know how long each line will be.
If you wanted you could add (?=\.\D\d) to the end of the last filter to remove the "b3" or any other letter/number combo, but this will only work on the last filter, it will not work if the text length is shorter that 5 filters long, as in this example.

D.