The thread referred to has the whole answer. I don't understand why you have anything else to ask if you read it carefully. Basically, if an amp is located at the antenna and has a power supply located someplace else, then DC is sent from someplace else up to the antenna. If you diplex that signal, the DC will be blocked and your amplifier will not get any power. It will then give you much less signal than you would get with the same antenna and NO amplifier. But let's carry on with the quesion:
On February 26, 2006 at 10:27, william david design said...
Thanks for the info. One clarification to the
scenario: The amplifier is an RCA (sic) and it
is powered from a 120 volt outlet in attic.
Why the (sic)? I am used to seeing this where someone says something not quite rite (sic) to indicate that you are quoting a misstep, as in this sentence.
More important than where the power comes from, where is the power injected into the cable? If it is injected downstream from the multiswitch, the multiswitch will block it so it can't go up to the antenna. If you are injecting it between the multiswitch and the antenna on a line that also has a satellite signal on it, you are screwing up the satellite signal because a DC voltage that is set to 13 or 17 volts, depending on the station, is part of the receiver's method of getting stations. You can't mix antenna power with satellite signal. No way, nohow.
Does
that mean I am not sending voltage through the
ant side of the diplexers by keeping the D/C block
in line?
Diplexers mix a satellite signal, which has DC voltage and perhaps tone, with antenna or cable signals. Any DC voltage on the cable or antenna wires do not pass through any diplexers.
And, do I add another D/C block on the
5in 8out multiswitch to stop any voltage from
backfeeding to the antenna to prevent loss of
reception???
You don't need to add a DC block on the multiswitch, because things already won't work because the multiswitch's UHF/VF input blocks DC automatically.