Impaqt,
I believe you have the diodes backwards in your drawing. I'm assuming the red lead of the emitter is the anode (usually connected to positive.)
The way you have it now, as the + lead rises in voltage, the voltage is blocked from going to the emitter. The emitter will never be turned on by either device.
If you reverse both diodes, the anode of both diodes connect to the positive terminals, and the cathode (banded end) connects to the anode of the emitter, the solution will work. When the top positive terminal is driven high, the top diode conducts and the emitter turns on, the bottom diode is reverse biased, so no voltage shows up at the lower + input, protecting that equipments output stage.
Also, rather than zener diodes, I would recommend schottky diodes. The zener diodes are designed to break down when a voltage above some threshold is applied, in this circuit, this behavior is not desireable. The schottky diodes have a lower forward voltage drop, and will drive the emitter more strongly.
Note: Impaqt has fixed the drawing earlier in this thread... Go by the drawing, and it should work!
Last edited by bcf1963
on February 7, 2006 16:29.