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Topic:  Wired Doorbell with 2 buttons 6 chimes This thread has 33 replies. Displaying posts 31 through 34. 

Post 31 made on Sunday August 12, 2018 at 10:33 
Ernie Gilman Yes, That Ernie! 
Joined: Posts:  December 2001 29,026 


Well, that's a switch!

A good answer is easier with a clear question giving the make and model of everything. "The biggest problem in communication is the illusion that it has taken place."  G. “Bernie” Shaw 

Post 32 made on Monday August 13, 2018 at 05:22 
Mario Loyal Member 
Joined: Posts:  November 2006 5,626 


On August 9, 2018 at 08:08, highfigh said...
If the house's floor plan was a circle, the farthest point from the center would be a little more than 164'. You meant 97ft, right? Circle is also the most efficient shape when it comes to minimizing distance from center.



Post 33 made on Monday August 13, 2018 at 08:53 
highfigh Loyal Member 
Joined: Posts:  September 2004 7,078 


On August 13, 2018 at 05:22, Mario said...
You meant 97ft, right? Circle is also the most efficient shape when it comes to minimizing distance from center. I didn't finish my calculation 164' is the square root of 27K so if it's a circle, 97' is close enough.

My mechanic told me, "I couldn't repair your brakes, so I made your horn louder." 

Post 34 made on Monday August 13, 2018 at 13:02 
Ernie Gilman Yes, That Ernie! 
Joined: Posts:  December 2001 29,026 


The calculation might have been incomplete, but it must have been done wrong, too. You get the number 164 if you ignore pi and take the square root of the area. Taking the square root of the area means taking the square root of pi, though, and pi is not squared in the formula for area of a circle.
First you divide the area, 27000, by pi, giving you 8261; then you take the square root of that and get 92.8. That's a maximum length of 93 feet of wire from the center of a circle to any place on the circumference, going in a straight line. Which won't happen.
So how much help is that? Quite enough for a round or square house. If the area were a square, it would be 164 feet on a side, or 82 feet from the center to the closest edge. To a corner it would be that times the square root of two, which is 116 feet, only 13% more than the similar number for a circle.
This gives a reasonable ballpark idea that you can count on distances being more than a hundred feet. How much more? It depends on how much the house differs from a square. If its "aspect ratio" is 2:1, 27,000 feet would be 116 x 232, so center to corner would be 129 feet.
Allowing for the fact that the house WON'T be a circle or square, but could easily be a 2:1 rectangle and not allowing for a tweaky shape, it seems reasonable to plan for at least 150 foot runs.
Did I mess up the arithmetic? Please check. And thanks. That was fun.

A good answer is easier with a clear question giving the make and model of everything. "The biggest problem in communication is the illusion that it has taken place."  G. “Bernie” Shaw 


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