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Original thread:
Post 3 made on Friday July 24, 2009 at 08:17
LECS
Long Time Member
Joined:
Posts:
July 2009
14
The checksum is calculated by adding together all the preceeding bytes, discarding anything over 1 byte, then ORing together with 7F.
So for the play example:

0x85 +
0x7f +
0x7f +
0x4B +
0x0B
=======
0x1D9

Discarding anything over 1 byte gives 0xD9, then

0xD9 OR 0x7F = 0x59.

daniel, was it the checksum you were having problems with, or something else?


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